(2z+3)^2+3z+3z=106

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Solution for (2z+3)^2+3z+3z=106 equation: 



(2z+3)^2+3z+3z=106

We move all terms to the left:

(2z+3)^2+3z+3z-(106)=0

We add all the numbers together, and all the variables

6z+(2z+3)^2-106=0

We move all terms containing z to the left, all other terms to the right

6z+(2z+3)^2=106

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